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NEET PHYSICSMOTION IN A PLANEEasy

Question

For a smoothly running analog clock, the ratio of the number of rotations made in a day by the hour hand to the second hand, respectively, is:

A

24 : 1

B

1 : 720

C

1 : 60

D

2 : 5

Step-by-Step Solution

  1. Analyze the Motion of the Hour Hand: The hour hand completes one full rotation in 12 hours. In one day (24 hours), the number of rotations made by the hour hand is: Nhour=24 hours12 hours/rotation=2 rotationsN_{hour} = \frac{24 \text{ hours}}{12 \text{ hours/rotation}} = 2 \text{ rotations}

  2. Analyze the Motion of the Second Hand: The second hand completes one full rotation in 1 minute. There are 24×60=144024 \times 60 = 1440 minutes in a day.

  • Therefore, in one day, the number of rotations made by the second hand is: Nsecond=1440 rotationsN_{second} = 1440 \text{ rotations}
  1. Calculate the Ratio: The ratio of the number of rotations of the hour hand to the second hand is: Ratio=NhourNsecond=21440\text{Ratio} = \frac{N_{hour}}{N_{second}} = \frac{2}{1440} Simplifying the fraction: Ratio=1720\text{Ratio} = \frac{1}{720}
  • Thus, the ratio is 1:7201:720.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEsmoothlyrunninganalognumberrotations

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