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NEET PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEEasy

Question

Four point charges -Q, -q, 2q and 2Q are placed, one at each corner of the square. The relation between Q and q for which the potential at the centre of the square is zero, is

A

Q = -q

B

Q = -1/q

C

Q = q

D

Q = 1/q

Step-by-Step Solution

  1. Formula for Potential: The electric potential VV at a distance rr from a point charge qq is given by V=14πε0qrV = \frac{1}{4\pi\varepsilon_0} \frac{q}{r} [1].
  2. Superposition Principle: The total potential at a point due to a system of charges is the algebraic sum of the potentials due to the individual charges [2].
  3. Application to Square: Let the distance from the centre of the square to each corner be rr. Since the point is the centre, rr is the same for all four charges.
  4. Calculation: The total potential VcenterV_{center} is: Vcenter=14πε0r(Qq+2q+2Q)V_{center} = \frac{1}{4\pi\varepsilon_0 r} (-Q - q + 2q + 2Q) For the potential to be zero (Vcenter=0V_{center} = 0), the term in the parentheses must be zero: Qq+2q+2Q=0-Q - q + 2q + 2Q = 0 Q+q=0Q + q = 0 Q=qQ = -q

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROSTATIC POTENTIAL AND CAPACITANCE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEchargesplacedcornersquarerelation

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