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NEET PHYSICSThermodynamicsMedium

Question

One mole of an ideal gas from an initial state A undergoes via two processes. It first undergoes isothermal expansion from volume VV to 3V3V and then its volume is reduced from 3V3V to VV at constant pressure. The correct PVP-V diagram representing the two processes is -

A

Option 1

B

Option 2

C

Option 3

D

Option 4

Step-by-Step Solution

The thermodynamic processes are as follows:

  1. Isothermal expansion from volume VV to 3V3V: According to Boyle's law, P1VP \propto \frac{1}{V} at constant temperature. On a PVP-V diagram, this is represented by a curve (rectangular hyperbola) where pressure decreases as volume increases.
  2. Isobaric compression from volume 3V3V to VV: At constant pressure, the volume decreases. On a PVP-V diagram, this is represented by a horizontal straight line parallel to the volume axis, moving from right to left. The correct diagram will show a downward curve followed by a horizontal line moving leftwards back to the initial volume.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermodynamicsinitialundergoesprocessesundergoesisothermal

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