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NEET PHYSICSThermodynamicsEasy

Question

One mole of an ideal gas goes from an initial state AA to the final state BB with two processes. It first undergoes isothermal expansion from volume VV to 3V3V and then its volume is reduced from 3V3V to VV at constant pressure. The correct (PV)(P-V) diagram representing the two processes is:

A

Option 1

B

Option 2

C

Option 3

D

Option 4

Step-by-Step Solution

The thermodynamic path consists of two distinct processes:

  1. Isothermal Expansion: The gas expands from volume VV to 3V3V at constant temperature (TT). For an ideal gas, PV=nRTPV = nRT . Since TT is constant, P1/VP \propto 1/V (Boyle's Law). On a PVP-V diagram, this is represented by a hyperbolic curve sloping downwards from initial volume VV to 3V3V .

  2. Isobaric Compression: The gas is compressed from volume 3V3V back to VV at constant pressure. This is represented by a straight horizontal line moving from right (3V3V) to left (VV) .

Thus, the correct graph traces a curve downwards to the right, followed by a horizontal line to the left.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermodynamicsinitialprocessesundergoesisothermalexpansion

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