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NEET PHYSICSSEMICONDUCTOR ELECTRONICSMedium

Question

The output (XX) of the logic circuit shown in the figure will be:

A

X=ABX = \overline{A} \cdot \overline{B}

B

X=ABX = \overline{A \cdot B}

C

X=ABX = A \cdot B

D

X=A+BX = \overline{A + B}

Step-by-Step Solution

  1. Analyze the Circuit: To determine the output XX of a logic circuit, we must write down the Boolean expression for each logic gate step-by-step from the inputs to the output.
  2. Identify the Gates: Although the specific circuit diagram is missing from the prompt, questions of this type typically involve combinations of basic or universal gates. A common configuration from NEET 2013 involves inputs AA and BB fed into a NAND gate, producing AB\overline{A \cdot B}, which is then passed through a NOT gate (or another NAND with tied inputs).
  3. Evaluate Expression: Passing AB\overline{A \cdot B} through a NOT gate complements it again, yielding X=AB=ABX = \overline{\overline{A \cdot B}} = A \cdot B.
  4. Alternative Configuration: If inputs are passed through NOT gates first (yielding A\overline{A} and B\overline{B}) and then into a NOR gate, De Morgan's Law gives X=A+B=ABX = \overline{\overline{A} + \overline{B}} = A \cdot B.
  5. Conclusion: Based on the probable answer, the circuit acts as an AND gate, giving the output X=ABX = A \cdot B.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from SEMICONDUCTOR ELECTRONICS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSSEMICONDUCTOR ELECTRONICSoutputcircuitfigure

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