A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cat

Question

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy $75\%$ of octahedral voids. The formula of the compound is :

Accepted Answer

Let the number of anions (A) be $N$. Number of octahedral voids = $N$. Number of cations (C) = $75\% 	ext{ of } N = 0.75N = \frac{3}{4}N$. Ratio of C:A = $\frac{3}{4}N : N = 3:4$. Formula is $C_3A_4$.

Step-by-Step Solution

Practice All CHEMISTRY Questions