A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is: (

Question

A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is: (Given atomic mass of A = 64; B = 40; C = 32 u)

Accepted Answer

1. **Calculate Percentage of C:**
   $$ \%C = 100 - (\%A + \%B) = 100 - (32 + 20) = 48\% $$
2. **Calculate Relative Number of Moles:**
   Divide the percentage composition by the respective atomic masses.
   - For A: $\frac{32}{64} = 0.5$
   - For B: $\frac{20}{40} = 0.5$
   - For C: $\frac{48}{32} = 1.5$
3. **Determine Simplest Whole Number Ratio:**
   Divide each value by the smallest number of moles (0.5).
   - A: $\frac{0.5}{0.5} = 1$
   - B: $\frac{0.5}{0.5} = 1$
   - C: $\frac{1.5}{0.5} = 3$
4. **Conclusion:**
   The empirical formula is $A_1B_1C_3$ or $ABC_3$.

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