Solved: CHEMISTRY Question for NEET

neet CHEMISTRYMedium

Copper crystallises in fcc unit cell with cell edge length of $3.608 \times 10^{-8}$ cm. The density of copper is $8.92$ g cm $^{-3}$ . Calculate the atomic mass of copper.

$63.1$ u

$31.55$ u

$60$ u

$65$ u

Step-by-Step Solution

For an fcc unit cell, $Z = 4$ . The formula for density is $d = \frac{Z \times M}{a^3 \times N_A}$ . Rearranging for atomic mass $M$ : $M = \frac{d \times a^3 \times N_A}{Z}$ . Substituting the values: $M = \frac{8.92 \times (3.608 \times 10^{-8})^3 \times 6.023 \times 10^{23}}{4} \approx 63.08$ u.

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