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neet CHEMISTRYEasy

For a certain reaction, the rate =k[A]2[B]= k[A]^2[B], when the initial concentration of A is tripled keeping concentration of B constant, the initial rate would

A

Decrease by a factor of nine

B

Increase by a factor of six

C

Increase by a factor of nine

D

Increase by a factor of three

Step-by-Step Solution

Initial rate r1=k[A]2[B]r_1 = k[A]^2[B]. New rate r2=k[3A]2[B]=k(9[A]2)[B]=9×k[A]2[B]=9r1r_2 = k[3A]^2[B] = k(9[A]^2)[B] = 9 \times k[A]^2[B] = 9r_1. The rate increases by a factor of nine.

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