Question
Given below are two statements : Statement I : The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole-dipole interactions. Statement II : The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding. In the light of the above statements, choose the most appropriate answer from the given below
Both Statement I and Statement II are correct
Both Statement I and Statement II are incorrect
Statement I is correct but Statement II is incorrect
Statement I is incorrect but Statement II is correct
Statement I is correct because aldehydes and ketones have polar carbonyl groups leading to dipole-dipole interactions. Statement II is correct because alcohols exhibit intermolecular hydrogen bonding, which is stronger than dipole-dipole interactions, leading to higher boiling points for alcohols compared to aldehydes and ketones of similar molecular mass.
This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.
More CHEMISTRY Questions
The pollution due to oxides of sulphur gets enhanced due to the presence of: (a) particulate matter (b) ozone (c) hydrocarbons (d) hydrogen peroxide. Choose the most appropriate answer from the options given below:
Compound X on reaction with $O_3$ followed by $Zn/H_2O$ gives formaldehyde and 2-methylpropanal as products. The compound X is
Given below are two statements: Statement I: In Lucas test, primary, secondary and tertiary alcohols are distinguished on the basis of their reactivity with conc. $HCl + ZnCl_2$, known as Lucas Reagent. Statement II: Primary alcohols are most reactive and immediately produce turbidity at room temperature on reaction with Lucas Reagent. In the light of the above statements, choose the most appropriate answer from the options given below:
A dehydration reaction links two glucose molecules to product maltose. If the formula for glucose is $C_6H_{12}O_6$ then what is the formula for maltose?
Which of the following $P-V$ curve represents maximum work done?
The correct sequence of bond enthalpy of 'C—X' bond is :
Match List -I with List -II. List -I (Drug class): (a) Antacids, (b) Antihistamines, (c) Analgesics, (d) Antimicrobials. List -II (Drug molecule): (i) Salvarsan, (ii) Morphine, (iii) Cimetidine, (iv) Seldane. Choose the correct answer from the options given below:
Identify the final product [D] obtained in the following sequence of reactions. $CH_3CHO \xrightarrow[ii) H_3O^+]{i) LiAlH_4} [A] \xrightarrow{H_2SO_4, \Delta} [B] \xrightarrow{HBr} [C] \xrightarrow{Na/dry ether} [D]$
Why 32,000+ students choose TopperSquare
15,000+ Chapter MCQs
Physics, Chemistry, Biology — chapter-wise, topic-wise practice
AI Performance Analytics
Know your weak topics. Get a personalised study plan.
Full NEET Mock Tests
180 questions, timed, with detailed score analysis
PYQ Sets 2010–2024
15 years of past papers with solved explanations
No credit card · 30-second signup · Free forever plan included
This neet chemistry practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice chemistry sets →
Sign in to save your score, view detailed analytics, and bookmark tough questions for revision.
Sign In / Join FreeChapter-wise practice sets
Identify weak areas instantly
Step-by-step logic for every question