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neet CHEMISTRYEasy

The conductivity of centimolar solution of KCl at 25∘C25^{\circ}\text{C} is 0.0210 ohm−1 cm−10.0210 \text{ ohm}^{-1} \text{ cm}^{-1} and the resistance of the cell containing the solution at 25∘C25^{\circ}\text{C} is 60 ohm60 \text{ ohm}. The value of cell constant is

A

1.34 cm−11.34 \text{ cm}^{-1}

B

3.28 cm−13.28 \text{ cm}^{-1}

C

1.26 cm−11.26 \text{ cm}^{-1}

D

3.34 cm−13.34 \text{ cm}^{-1}

Step-by-Step Solution

The cell constant G∗G^* is given by the formula G∗=κ×RG^* = \kappa \times R, where κ\kappa is the conductivity and RR is the resistance. Given κ=0.0210 ohm−1 cm−1\kappa = 0.0210 \text{ ohm}^{-1} \text{ cm}^{-1} and R=60 ohmR = 60 \text{ ohm}, we have G∗=0.0210×60=1.26 cm−1G^* = 0.0210 \times 60 = 1.26 \text{ cm}^{-1}.

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