The correct option for the value of vapour pressure of a solution at $45^{\circ} ext{C}$ with benzene to octa

Question

The correct option for the value of vapour pressure of a solution at $45^{\circ}	ext{C}$ with benzene to octane in molar ratio $3:2$ is: [At $45^{\circ}	ext{C}$ vapour pressure of benzene is $280 	ext{ mm Hg}$ and that of octane is $420 	ext{ mm Hg}$. Assume Ideal gas]

Accepted Answer

Given $n_{	ext{C}_6	ext{H}_6} : n_{	ext{C}_8	ext{H}_{18}} = 3:2$. Mole fractions: $x_{	ext{C}_6	ext{H}_6} = 3/5$, $x_{	ext{C}_8	ext{H}_{18}} = 2/5$. Total pressure $P_s = P^{\circ}_A x_A + P^{\circ}_B x_B = 280 	imes (3/5) + 420 	imes (2/5) = 168 + 168 = 336 	ext{ mm Hg}$.

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