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NEET CHEMISTRYGeneralMedium

Question

The following solutions were prepared by dissolving 10 g of glucose (C6H12O6C_6H_{12}O_6) in 250 ml of water (P1P_1), 10 g of urea (CH4N2OCH_4N_2O) in 250 ml of water (P2P_2) and 10 g of sucrose (C12H22O11C_{12}H_{22}O_{11}) in 250 ml of water (P3P_3). The right option for the decreasing order of osmotic pressure of these solutions is :

1

P2>P1>P3P_2 > P_1 > P_3

2

P1>P2>P3P_1 > P_2 > P_3

3

P2>P3>P1P_2 > P_3 > P_1

4

P3>P1>P2P_3 > P_1 > P_2

Step-by-Step Solution

Osmotic pressure (π\pi) = iCRT. With increase in molar concentration of solution, osmotic pressure increases. Since weight of all solutes and its solution volume are equal, so higher will be the molar mass of solute, smaller will be the molar concentration and smaller will be the osmotic pressure. Order of molar mass of solute decreases as Sucrose > Glucose > Urea. So, correct order of osmotic pressure of solution is P3<P1<P2P_3 < P_1 < P_2.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYfollowingsolutionsprepareddissolvingglucose

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