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NEET CHEMISTRYAlcohols, Phenols and EthersEasy

Question

When phenol is treated with CHCl₃ and NaOH, the product formed is:

A

Benzaldehyde

B

Salicylaldehyde

C

Salicylic acid

D

Benzoic acid

Step-by-Step Solution

The reaction described is the Reimer-Tiemann reaction. When phenol is treated with chloroform (CHCl3CHCl_3) in the presence of aqueous sodium hydroxide (NaOHNaOH), an aldehyde group (−CHO-CHO) is introduced at the ortho position of the benzene ring.

  1. Mechanism: The reaction proceeds via the formation of an electrophilic intermediate called dichlorocarbene (:CCl2:CCl_2).
  2. Product: The major product formed is Salicylaldehyde (2-Hydroxybenzaldehyde).

(Note: If Carbon tetrachloride, CCl4CCl_4, is used instead of Chloroform, the product is Salicylic acid).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Alcohols, Phenols and Ethers. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAlcohols, Phenols and Ethersphenoltreatedproductformed

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