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NEET PHYSICSThermal Properties of MatterMedium

Question

A black body is at a temperature of 5760 K5760 \text{ K}. The energy of radiation emitted by the body at wavelength 250 nm250 \text{ nm} is U1U_1, at wavelength 500 nm500 \text{ nm} is U2U_2 and that at 1000 nm1000 \text{ nm} is U3U_3. Wien's constant, b=2.88×106 nm Kb = 2.88 \times 10^6 \text{ nm K}. Which of the following is correct?

A

U3=0U_3 = 0

B

U1>U2U_1 > U_2

C

U2>U1U_2 > U_1

D

U1=0U_1 = 0

Step-by-Step Solution

According to Wien's displacement law, λmT=b\lambda_m T = b, where λm\lambda_m is the wavelength corresponding to maximum spectral emissive power, TT is the absolute temperature, and bb is Wien's constant. Given: T=5760 KT = 5760 \text{ K} and b=2.88×106 nm Kb = 2.88 \times 10^6 \text{ nm K}. λm=bT=2.88×1065760=500 nm\lambda_m = \frac{b}{T} = \frac{2.88 \times 10^6}{5760} = 500 \text{ nm}. Therefore, the maximum energy is radiated at a wavelength of 500 nm500 \text{ nm}. Since U2U_2 corresponds to the energy radiated at 500 nm500 \text{ nm}, it is the maximum among the given energies. Thus, U2>U1U_2 > U_1 and U2>U3U_2 > U_3. Also, a black body emits continuous radiation over all wavelengths, so U10U_1 \neq 0 and U30U_3 \neq 0. The only correct statement among the options is U2>U1U_2 > U_1.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermal Properties of Matter. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermal Properties of Mattertemperatureenergyradiationemittedwavelength

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