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NEET PHYSICSELECTROMAGNETIC INDUCTIONMedium

Question

A conducting circular loop is placed in a uniform magnetic field 0.04 T0.04\text{ T} with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2 mm/s2\text{ mm/s}. The induced emf in the loop when the radius is 2 cm2\text{ cm} is:

A

3.2πμV3.2\pi\mu\text{V}

B

4.8πμV4.8\pi\mu\text{V}

C

0.8πμV0.8\pi\mu\text{V}

D

1.6πμV1.6\pi\mu\text{V}

Step-by-Step Solution

According to Faraday's Law of Induction, the magnitude of the induced emf (ε|\varepsilon|) is equal to the rate of change of magnetic flux (ΦB\Phi_B) .

  1. Formula: The magnetic flux through the loop is ΦB=BA=B(πr2)\Phi_B = B \cdot A = B(\pi r^2), where BB is the magnetic field and rr is the radius. Differentiating with respect to time tt: ε=dΦBdt=ddt(Bπr2)|\varepsilon| = \left| \frac{d\Phi_B}{dt} \right| = \left| \frac{d}{dt} (B \pi r^2) \right| Since BB is constant, we use the chain rule for the changing radius: ε=Bπd(r2)dt=Bπ(2r)drdt|\varepsilon| = B \pi \frac{d(r^2)}{dt} = B \pi (2r) \left| \frac{dr}{dt} \right|

  2. Given Values: Magnetic Field B=0.04 T=4×102 TB = 0.04 \text{ T} = 4 \times 10^{-2} \text{ T} Radius r=2 cm=2×102 mr = 2 \text{ cm} = 2 \times 10^{-2} \text{ m}

  • Rate of shrinking drdt=2 mm/s=2×103 m/s\left| \frac{dr}{dt} \right| = 2 \text{ mm/s} = 2 \times 10^{-3} \text{ m/s}
  1. Calculation: Substituting the values into the derived equation: ε=(4×102)×π×2(2×102)×(2×103)|\varepsilon| = (4 \times 10^{-2}) \times \pi \times 2(2 \times 10^{-2}) \times (2 \times 10^{-3}) ε=(4×2×2×2)π×10223|\varepsilon| = (4 \times 2 \times 2 \times 2) \pi \times 10^{-2-2-3} ε=32π×107 V|\varepsilon| = 32 \pi \times 10^{-7} \text{ V} ε=3.2π×106 V|\varepsilon| = 3.2 \pi \times 10^{-6} \text{ V} Since 106 V=1μV10^{-6} \text{ V} = 1 \mu\text{V}: ε=3.2πμV|\varepsilon| = 3.2\pi \mu\text{V}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROMAGNETIC INDUCTION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROMAGNETIC INDUCTIONconductingcircularplaceduniformmagnetic

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