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NEET PHYSICSELECTROMAGNETIC INDUCTIONEasy

Question

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ\phi linked with the primary coil is given by ϕ=ϕ0+4t\phi = \phi_0 + 4t, where ϕ\phi is in Weber, tt is time in seconds, and ϕ0\phi_0 is a constant, the output voltage across the secondary coil is:

A

90 V

B

120 V

C

220 V

D

30 V

Step-by-Step Solution

  1. Induced EMF in Primary (VpV_p): According to Faraday's law of induction, the induced electromotive force (emf) is the rate of change of magnetic flux. Given the flux linked with the primary coil is ϕ=ϕ0+4t\phi = \phi_0 + 4t, the induced voltage in the primary is: Vp=dϕdt=ddt(ϕ0+4t)=4 VV_p = \left| \frac{d\phi}{dt} \right| = \frac{d}{dt}(\phi_0 + 4t) = 4 \text{ V}

  2. Transformer Equation: For an ideal transformer, the ratio of voltages across the primary and secondary coils is equal to the ratio of their number of turns: VsVp=NsNp\frac{V_s}{V_p} = \frac{N_s}{N_p} Where: VsV_s is the secondary voltage (output). Vp=4 VV_p = 4 \text{ V} (primary voltage). Ns=1500N_s = 1500 (secondary turns). Np=50N_p = 50 (primary turns).

  3. Calculation: Vs=Vp×NsNpV_s = V_p \times \frac{N_s}{N_p} Vs=4×150050V_s = 4 \times \frac{1500}{50} Vs=4×30V_s = 4 \times 30 Vs=120 VV_s = 120 \text{ V}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROMAGNETIC INDUCTION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROMAGNETIC INDUCTIONprimarysecondarytransformerrespectivelymagnetic

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