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NEET PHYSICSELECTROMAGNETIC INDUCTIONEasy

Question

Two coils of self-inductance 2 mH2 \text{ mH} and 8 mH8 \text{ mH} are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is:

A

10 mH

B

6 mH

C

4 mH

D

16 mH

Step-by-Step Solution

The mutual inductance (MM) between two coils with self-inductances L1L_1 and L2L_2 is related by the formula: M=kL1L2M = k \sqrt{L_1 L_2} Where kk is the coefficient of coupling, which ranges from 0 to 1.

Condition: The problem states that the effective flux in one coil is completely linked with the other. This implies perfect coupling, so k=1k = 1 .

Calculation: L1=2 mHL_1 = 2 \text{ mH} L2=8 mHL_2 = 8 \text{ mH}

  • k=1k = 1

M=1×2×8M = 1 \times \sqrt{2 \times 8} M=16M = \sqrt{16} M=4 mHM = 4 \text{ mH}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROMAGNETIC INDUCTION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROMAGNETIC INDUCTIONselfinductanceplacedtogethereffectivecompletely

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