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NEET PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEEasy

Question

A conducting sphere of radius R is given a charge Q. The electric potential and the electric field at the centre of the sphere respectively are:

A

Zero and Q/(4\pi ε₀R²)

B

Q/(4\pi ε₀R) and Zero

C

Q/(4\pi ε₀R) and Q/(4\pi ε₀R²)

D

Both are zero

Step-by-Step Solution

  1. Electric Field: According to the properties of electrostatics of conductors, the net electrostatic field inside a charged conductor is zero everywhere. This applies to the entire volume, including the centre. Thus, Ecenter=0E_{center} = 0 [1].
  2. Electric Potential: Since the electric field inside is zero (E=−dV/dr=0E = -dV/dr = 0), the potential is constant throughout the volume of the conductor and has the same value as on its surface. The potential on the surface of a conducting sphere of radius RR and charge QQ is given by V=14πε0QRV = \frac{1}{4\pi\varepsilon_0}\frac{Q}{R}. Therefore, the potential at the centre is also Q4πε0R\frac{Q}{4\pi\varepsilon_0 R} [2], [1].

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROSTATIC POTENTIAL AND CAPACITANCE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROSTATIC POTENTIAL AND CAPACITANCEconductingsphereradiuschargeelectric

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