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NEET PHYSICSKinetic TheoryMedium

Question

A container of volume 200 cm3200 \text{ cm}^3 contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature 200 K200 \text{ K} (R=8.3 J K1 mol1R = 8.3 \text{ J K}^{-1} \text{ mol}^{-1}) will be:

A

6.15 × 10⁵ Pa

B

6.15 × 10⁴ Pa

C

4.15 × 10⁵ Pa

D

4.15 × 10⁶ Pa

Step-by-Step Solution

According to Dalton's Law of Partial Pressures, the total pressure exerted by a mixture of non-reactive gases is the sum of the partial pressures of individual gases. Alternatively, using the Ideal Gas Equation PV=nRTPV = nRT for the total mixture:

  1. Calculate Total Moles (nn): n=nH2+nAr=0.2+0.3=0.5 moln = n_{H_2} + n_{Ar} = 0.2 + 0.3 = 0.5 \text{ mol}

  2. Convert Volume to SI Units (VV): V=200 cm3=200×106 m3=2×104 m3V = 200 \text{ cm}^3 = 200 \times 10^{-6} \text{ m}^3 = 2 \times 10^{-4} \text{ m}^3

  3. Apply Ideal Gas Equation: P=nRTVP = \frac{nRT}{V} P=0.5×8.3×2002×104P = \frac{0.5 \times 8.3 \times 200}{2 \times 10^{-4}} P=8302×104P = \frac{830}{2 \times 10^{-4}} P=415×104 PaP = 415 \times 10^4 \text{ Pa} P=4.15×106 PaP = 4.15 \times 10^6 \text{ Pa}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Kinetic Theory. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSKinetic Theorycontainervolumecontainshydrogenpressure

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