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NEET PHYSICSKinetic TheoryEasy

Question

In the given V-T diagram, what is the relation between pressure P1P_1 and P2P_2?

A

P2>P1P_2 > P_1

B

P2<P1P_2 < P_1

C

cannot be predicted

D

P2=P1P_2 = P_1

Step-by-Step Solution

  1. Analyze the Ideal Gas Equation: The behavior of an ideal gas is governed by the equation PV=nRTPV = nRT .
  2. Analyze the V-T Graph: The diagram plots Volume (VV) versus Temperature (TT). Rearranging the ideal gas equation to express VV as a function of TT (keeping Pressure PP constant for each line) gives V=(nRP)TV = \left(\frac{nR}{P}\right)T. This is the equation of a straight line y=mxy = mx passing through the origin.
  3. Slope-Pressure Relationship: The slope of the line (mm) is equal to nRP\frac{nR}{P}. Since nn and RR are constants, the slope is inversely proportional to the pressure (m1Pm \propto \frac{1}{P}). This means a line with a steeper slope (higher VV for a given TT) corresponds to a lower pressure.
  4. Conclusion: For the relation P2<P1P_2 < P_1 to be true, the line corresponding to P2P_2 must have a larger slope (be closer to the V-axis) than the line corresponding to P1P_1. Conversely, the line with the smaller slope represents the higher pressure (P1P_1).

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Kinetic Theory. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSKinetic Theorydiagramrelationbetweenpressure

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