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NEET PHYSICSKinetic TheoryMedium

Question

The temperature of a gas is 50C-50^\circ\text{C}. To what temperature the gas should be heated so that the RMS speed is increased by 3 times?

A

223 K

B

669^\circ\text{C}

C

3295^\circ\text{C}

D

3097 K

Step-by-Step Solution

The root mean square speed (vrmsv_{rms}) is directly proportional to the square root of the absolute temperature (vrmsTv_{rms} \propto \sqrt{T}).

  1. Initial State: T1=50C=27350=223 KT_1 = -50^\circ\text{C} = 273 - 50 = 223 \text{ K}. Let the initial speed be v1=vv_1 = v.

  2. Final State: The speed is increased by 3 times. This means the final speed v2=v+3v=4vv_2 = v + 3v = 4v.

  3. Calculation: Using the relation v2v1=T2T1\frac{v_2}{v_1} = \sqrt{\frac{T_2}{T_1}}: 4vv=T2223\frac{4v}{v} = \sqrt{\frac{T_2}{223}} 4=T22234 = \sqrt{\frac{T_2}{223}} Squaring both sides: 16=T222316 = \frac{T_2}{223} T2=16×223=3568 KT_2 = 16 \times 223 = 3568 \text{ K}

  4. Conversion: Convert the final temperature back to Celsius: T2(in C)=3568273=3295CT_2 (\text{in } ^\circ\text{C}) = 3568 - 273 = 3295^\circ\text{C}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Kinetic Theory. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSKinetic Theorytemperaturecirctextctemperatureshouldheated

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