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NEET PHYSICSOscillationsMedium

Question

A simple pendulum performs simple harmonic motion about x=0x = 0 with an amplitude aa and time period TT. The speed of the pendulum at x=a2x = \frac{a}{2} will be:

A

πa32T\frac{\pi a \sqrt{3}}{2T}

B

πaT\frac{\pi a}{T}

C

3π2aT\frac{3\pi^2 a}{T}

D

πa3T\frac{\pi a \sqrt{3}}{T}

Step-by-Step Solution

  1. Identify the Speed Equation in SHM: The speed vv of a particle executing simple harmonic motion at a displacement xx from the mean position is given by v=ωA2x2v = \omega \sqrt{A^2 - x^2}, where AA is the amplitude and ω\omega is the angular frequency.
  2. Substitute Given Values:
  • Amplitude A=aA = a
  • Displacement x=a2x = \frac{a}{2}
  • Angular frequency ω=2πT\omega = \frac{2\pi}{T}
  1. Calculate Speed: v=2πTa2(a2)2v = \frac{2\pi}{T} \sqrt{a^2 - \left(\frac{a}{2}\right)^2} v=2πTa2a24v = \frac{2\pi}{T} \sqrt{a^2 - \frac{a^2}{4}} v=2πT3a24v = \frac{2\pi}{T} \sqrt{\frac{3a^2}{4}} v=2πTa32=πa3Tv = \frac{2\pi}{T} \cdot \frac{a\sqrt{3}}{2} = \frac{\pi a \sqrt{3}}{T}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Oscillations. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSOscillationssimplependulumperformssimpleharmonic

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