A thin spherical shell is charged by some source. The potential difference between the two points C and P (in

Question

A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is: (Take 1/4πε₀ = 9 × 10⁹ SI units)

Accepted Answer

1. **Electric Field Inside a Shell:** For a uniformly charged thin spherical shell, the electric field inside the shell is zero everywhere. This is analogous to the gravitational field inside a spherical shell of uniform density being zero, as discussed in classical mechanics [1].
2. **Relation to Potential:** The electric field ($E$) is related to the electric potential ($V$) by the gradient relationship $E = -dV/dr$. Since $E = 0$ inside the shell, the change in potential ($dV$) is zero.
3. **Constant Potential:** This implies that the electric potential is constant throughout the interior of the shell and is equal to the potential at the surface. 
4. **Conclusion:** Since both points $C$ (presumably the center) and $P$ (a point inside) are within the interior region where potential is constant, the potential difference between them is zero ($V_C - V_P = 0$).

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