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NEET PHYSICSMOVING CHARGES AND MAGNETISMMedium

Question

A voltmeter has a resistance of GG ohms and range VV volts. The value of resistance used in series to convert it into a voltmeter of range nVnV volts is:

A

nGnG

B

(n1)G(n-1)G

C

Gn\frac{G}{n}

D

Gn1\frac{G}{n-1}

Step-by-Step Solution

  1. Principle: To increase the range of a voltmeter, a high resistance (RR) is connected in series with the galvanometer (or existing voltmeter coil) .
  2. Initial Condition: Let IgI_g be the current required for full-scale deflection. With resistance GG and range VV, Ohm's law gives V=IgGV = I_g G.
  3. New Condition: We want the new range to be V=nVV' = nV. We connect a resistance RR in series. The total resistance becomes (G+R)(G + R).
  4. Equation: The new voltage range corresponds to the same full-scale current IgI_g flowing through the series combination: V=Ig(G+R)V' = I_g (G + R) Substituting V=nVV' = nV and Ig=V/GI_g = V/G: nV=VG(G+R)nV = \frac{V}{G} (G + R) n=G+RGn = \frac{G + R}{G} n=1+RGn = 1 + \frac{R}{G} RG=n1\frac{R}{G} = n - 1 R=(n1)GR = (n - 1)G.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOVING CHARGES AND MAGNETISM. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOVING CHARGES AND MAGNETISMvoltmeterresistanceresistanceseriesconvert

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