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NEET PHYSICSThermal Properties of MatterEasy

Question

If the cold junction of a thermocouple is kept at 0C0^\circ\text{C} and the hot junction is kept at TCT^\circ\text{C}, then the relation between neutral temperature (TnT_n) and temperature of inversion (TiT_i) is:

A

Tn=Ti2T_n = \frac{T_i}{2}

B

Tn=2TiT_n = 2T_i

C

Tn=TiTT_n = T_i - T

D

Tn=Ti+TT_n = T_i + T

Step-by-Step Solution

For a given thermocouple, the temperature difference between the neutral temperature (TnT_n) and the cold junction temperature (TcT_c) is equal to the temperature difference between the inversion temperature (TiT_i) and the neutral temperature (TnT_n). This can be mathematically expressed as: TnTc=TiTnT_n - T_c = T_i - T_n     2Tn=Ti+Tc\implies 2T_n = T_i + T_c Given that the cold junction is kept at 0C0^\circ\text{C} (Tc=0CT_c = 0^\circ\text{C}), 2Tn=Ti+02T_n = T_i + 0     Tn=Ti2\implies T_n = \frac{T_i}{2}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermal Properties of Matter. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermal Properties of Matterjunctionthermocouplecirctextcjunctiontcirctextc

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