Let $T_1$ and $T_2$ be the energy of an electron in the first and second excited states of hydrogen atoms, res

Question

Let $T_1$ and $T_2$ be the energy of an electron in the first and second excited states of hydrogen atoms, respectively. According to the Bohr's model of an atom, the ratio $T_1 : T_2$ is

Accepted Answer

$E_n = \frac{E_0}{n^2}$. For first excited state, $n = 2$. For second excited state, $n = 3$. Therefore, $\frac{T_1}{T_2} = \frac{E_0/2^2}{E_0/3^2} = \frac{1/4}{1/9} = \frac{9}{4}$.

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