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NEET PHYSICSMOTION IN A STRAIGHT LINEMedium

Question

The velocity of a bullet is reduced from 200 m/s200 \text{ m/s} to 100 m/s100 \text{ m/s} while travelling through a wooden block of thickness 10 cm10 \text{ cm}. The retardation, assuming it to be uniform, will be:

A

10×104 m/s210 \times 10^4 \text{ m/s}^2

B

12×104 m/s212 \times 10^4 \text{ m/s}^2

C

13.5×104 m/s213.5 \times 10^4 \text{ m/s}^2

D

15×104 m/s215 \times 10^4 \text{ m/s}^2

Step-by-Step Solution

  1. Identify Given Values: Initial velocity, u=200 m/su = 200 \text{ m/s}. Final velocity, v=100 m/sv = 100 \text{ m/s}.
  • Displacement (thickness), s=10 cm=0.1 ms = 10 \text{ cm} = 0.1 \text{ m} (Note: Unit conversion is crucial).
  1. Select Formula: Use the kinematic equation relating velocity, acceleration, and displacement: v2=u2+2asv^2 = u^2 + 2as .
  2. Calculation: (100)2=(200)2+2a(0.1)(100)^2 = (200)^2 + 2a(0.1) 10000=40000+0.2a10000 = 40000 + 0.2a 0.2a=10000400000.2a = 10000 - 40000 0.2a=300000.2a = -30000 a=300000.2=150000 m/s2a = \frac{-30000}{0.2} = -150000 \text{ m/s}^2.
  3. Scientific Notation: Magnitude of acceleration (retardation) =150000 m/s2=15×104 m/s2= 150000 \text{ m/s}^2 = 15 \times 10^4 \text{ m/s}^2.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEvelocitybulletreducedtravellingthrough

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