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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

The displacement of a particle, moving in a straight line, is given by s=2t2+2t+4s = 2t^2 + 2t + 4 where ss is in metres and tt in seconds. The acceleration of the particle is:

A

2 m/s²

B

4 m/s²

C

6 m/s²

D

8 m/s²

Step-by-Step Solution

  1. Velocity (vv): Instantaneous velocity is defined as the rate of change of displacement with respect to time (v=dsdtv = \frac{ds}{dt}) . Given s=2t2+2t+4s = 2t^2 + 2t + 4. Differentiating with respect to tt: v=ddt(2t2+2t+4)=4t+2v = \frac{d}{dt}(2t^2 + 2t + 4) = 4t + 2.
  2. Acceleration (aa): Instantaneous acceleration is defined as the rate of change of velocity with respect to time (a=dvdta = \frac{dv}{dt}) . Differentiating vv with respect to tt: a=ddt(4t+2)=4a = \frac{d}{dt}(4t + 2) = 4.
  3. Result: The acceleration is constant at 4 m/s24 \text{ m/s}^2.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEdisplacementparticlemovingstraightmetres

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