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Question

The determination of the value of acceleration due to gravity (gg) by simple pendulum method employs the formula, g=4π2LT2g = 4\pi^2 \frac{L}{T^2}. The expression for the relative error in the value of gg is:

A

Δgg=ΔLL+2(ΔTT)\frac{\Delta g}{g} = \frac{\Delta L}{L} + 2\left(\frac{\Delta T}{T}\right)

B

Δgg=4π2[ΔLL2ΔTT]\frac{\Delta g}{g} = 4\pi^2 \left[\frac{\Delta L}{L} - 2\frac{\Delta T}{T}\right]

C

Δgg=4π2[ΔLL+2ΔTT]\frac{\Delta g}{g} = 4\pi^2 \left[\frac{\Delta L}{L} + 2\frac{\Delta T}{T}\right]

D

Δgg=ΔLL2(ΔTT)\frac{\Delta g}{g} = \frac{\Delta L}{L} - 2\left(\frac{\Delta T}{T}\right)

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