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NEET PHYSICSUNITS AND MEASUREMENTSMedium

Question

In an experiment, four quantities aa, bb, cc and dd are measured with percentage error 1%1\%, 2%2\%, 3%3\% and 4%4\% respectively. Quantity PP is calculated as follows: P=a3b2cdP=\frac{a^3b^2}{cd}. Percentage error in PP is:

A

10%10\%

B

7%7\%

C

4%4\%

D

14%14\%

Step-by-Step Solution

  1. Identify the Given Formula: The quantity PP is given by P=a3b2cdP = \frac{a^3b^2}{cd}.
  2. Apply Error Propagation Rules: For a quantity that is a product or quotient of other quantities, the maximum relative error is the sum of the relative errors of the individual quantities multiplied by their respective powers. Thus, ΔPP=3Δaa+2Δbb+Δcc+Δdd\frac{\Delta P}{P} = 3\frac{\Delta a}{a} + 2\frac{\Delta b}{b} + \frac{\Delta c}{c} + \frac{\Delta d}{d}.
  3. Calculate Percentage Error: Multiplying by 100100 converts this to percentage error: % error in P=3(% error in a)+2(% error in b)+(% error in c)+(% error in d)\% \text{ error in } P = 3(\% \text{ error in } a) + 2(\% \text{ error in } b) + (\% \text{ error in } c) + (\% \text{ error in } d).
  4. Substitute Given Values: % error in P=3(1%)+2(2%)+1(3%)+1(4%)\% \text{ error in } P = 3(1\%) + 2(2\%) + 1(3\%) + 1(4\%) % error in P=3%+4%+3%+4%=14%\% \text{ error in } P = 3\% + 4\% + 3\% + 4\% = 14\%.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSexperimentquantitiesmeasuredpercentagerespectively

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