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Question

The dimensions of Planck's constant and angular momentum are respectively:

A

ML2T1ML^2 T^{-1} and MLT1MLT^{-1}

B

ML2T1ML^2 T^{-1} and ML2T1ML^2 T^{-1}

C

MLT1MLT^{-1} and ML2T1ML^2 T^{-1}

D

MLT1MLT^{-1} and ML2T2ML^2 T^{-2}

Step-by-Step Solution

To find the dimensions of Planck's constant and angular momentum, we examine their defining equations:

  1. Planck's Constant (hh): According to Planck's quantum theory, the energy (EE) of a quantum of radiation is given by E=hνE = h\nu, where ν\nu is the frequency . From the sources, energy has the dimensions [ML2T2][ML^2T^{-2}] and frequency has the dimension [T1][T^{-1}] . Therefore, the dimensions of hh are [ML2T2]/[T1]=[ML2T1][ML^2T^{-2}] / [T^{-1}] = [ML^2T^{-1}] .

  2. Angular Momentum (LL): Angular momentum is defined as the product of mass (mm), velocity (vv), and radius (rr), expressed as L=mvrL = mvr . Mass has the dimension [M][M], velocity has dimensions [LT1][LT^{-1}], and radius has the dimension [L][L]. Thus, the dimensions of angular momentum are [M]×[LT1]×[L]=[ML2T1][M] \times [LT^{-1}] \times [L] = [ML^2T^{-1}] .

Since both physical quantities share the same dimensional formula, the correct pair is [ML2T1][ML^2 T^{-1}] and [ML2T1][ML^2 T^{-1}], which corresponds to Option B.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSdimensionsplancksconstantangularmomentum

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