back to directory
NEET PHYSICSKinetic TheoryEasy

Question

The following graph represents the T-V curves of an ideal gas (where T is the temperature and V the volume) at three pressures P1,P2P_1, P_2 and P3P_3 compared with those of Charles's law represented as dotted lines. Then the correct relation is:

A

P1>P3>P2P_1 > P_3 > P_2

B

P2>P1>P3P_2 > P_1 > P_3

C

P1>P2>P3P_1 > P_2 > P_3

D

P3>P2>P1P_3 > P_2 > P_1

Step-by-Step Solution

The Ideal Gas Equation is given by PV=nRTPV = nRT.

  1. Analyze the Graph Axes: The problem specifies 'T-V curves', which implies Temperature (TT) is plotted on the y-axis and Volume (VV) on the x-axis.
  2. Determine the Slope: Rearranging the ideal gas equation to express TT in terms of VV: T=(PnR)VT = \left(\frac{P}{nR}\right)V. This equation represents a straight line passing through the origin (y=mxy = mx) where the slope m=PnRm = \frac{P}{nR}.
  3. Relate Slope to Pressure: The slope is directly proportional to the pressure (mPm \propto P). Therefore, the curve with the steepest slope corresponds to the highest pressure, and the curve with the lowest slope corresponds to the lowest pressure.
  4. Conclusion: Assuming the lines are labeled 1, 2, and 3 in decreasing order of slope (as is standard for this specific PYQ where the answer is P1>P2>P3P_1 > P_2 > P_3), line 1 has the highest pressure and line 3 has the lowest. Thus, P1>P2>P3P_1 > P_2 > P_3.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Kinetic Theory. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSKinetic Theoryfollowingrepresentscurvestemperaturevolume

More Kinetic Theory Questions

View all

The mean free path l for a gas molecule depends upon the diameter, d of the molecule as:

A.l ∝ 1/d²
B.l ∝ d
C.l ∝ d²
D.l ∝ 1/d
EasySolve

The value $\gamma = \frac{C_P}{C_V}$ for hydrogen, helium, and another ideal diatomic gas $X$ (whose molecules are not rigid but have an additional vibrational mode), are respectively equal to:

A.$\frac{7}{5}, \frac{5}{3}, \frac{9}{7}$
B.$\frac{5}{3}, \frac{7}{5}, \frac{9}{7}$
C.$\frac{5}{3}, \frac{7}{5}, \frac{7}{5}$
D.$\frac{7}{5}, \frac{5}{3}, \frac{7}{5}$
MediumSolve

An ideal gas at $0^\circ\text{C}$ and atmospheric pressure $P$ has volume $V$. The percentage increase in its temperature needed to expand it to $3V$ at constant pressure is:

A.100%
B.200%
C.300%
D.50%
EasySolve

The root-mean-square speed of hydrogen molecules at 300 K is 1930 m/s. Then the root mean square speed of oxygen molecules at 900 K will be:

A.1930√3 m/s
B.836 m/s
C.643 m/s
D.1930/√3 m/s
MediumSolve

The molar specific heats of an ideal gas at constant pressure and volume are denoted by $C_P$ and $C_V$ respectively. If $\gamma = C_P/C_V$ and $R$ is the universal gas constant, then $C_V$ is equal to:

A.(1+\gamma)/(1-\gamma)
B.R/(\gamma-1)
C.(\gamma-1)/R
D.\gamma R
EasySolve

In the given V-T diagram, what is the relation between pressure $P_1$ and $P_2$?

A.$P_2 > P_1$
B.$P_2 < P_1$
C.cannot be predicted
D.$P_2 = P_1$
EasySolve

One mole of an ideal monatomic gas undergoes a process described by the equation $PV^3 = \text{constant}$. The heat capacity of the gas during this process is:

A.3/2 R
B.5/2 R
C.2 R
D.R
MediumSolve

The volume occupied by the molecules contained in $4.5 \text{ kg}$ water at STP, if the molecular forces vanish away, is:

A.$5.6 \text{ m}^3$
B.$5.6 \times 10^6 \text{ m}^3$
C.$5.6 \times 10^3 \text{ m}^3$
D.$5.6 \times 10^{-3} \text{ m}^3$
MediumSolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →