back to directory
NEET PHYSICSELECTROMAGNETIC INDUCTIONMedium

Question

Two conducting circular loops of radii R1R_1 and R2R_2 are placed in the same plane with their centres coinciding. If R1R2R_1 \gg R_2, the mutual inductance MM between them will be directly proportional to:

A

R1R2\frac{R_1}{R_2}

B

R2R1\frac{R_2}{R_1}

C

R12R2\frac{R_1^2}{R_2}

D

R22R1\frac{R_2^2}{R_1}

Step-by-Step Solution

This problem corresponds directly to Example 6.8 in the NCERT textbook .

  1. Setup: A current I1I_1 flows through the larger outer loop of radius R1R_1.
  2. Magnetic Field: The magnetic field B1B_1 produced at the center of the large loop is given by B1=μ0I12R1B_1 = \frac{\mu_0 I_1}{2R_1}. Since R1R2R_1 \gg R_2, this field is assumed to be uniform over the area of the smaller inner loop.
  3. Magnetic Flux: The magnetic flux Φ2\Phi_2 linked with the smaller loop (radius R2R_2) is the product of the field and the area of the small loop: Φ2=B1A2=(μ0I12R1)(πR22)\Phi_2 = B_1 A_2 = \left(\frac{\mu_0 I_1}{2R_1}\right) (\pi R_2^2).
  4. Mutual Inductance: By definition, Φ2=MI1\Phi_2 = M I_1. Comparing the expressions, we get M=μ0πR222R1M = \frac{\mu_0 \pi R_2^2}{2R_1}.
  5. Proportionality: Therefore, MR22R1M \propto \frac{R_2^2}{R_1}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ELECTROMAGNETIC INDUCTION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSELECTROMAGNETIC INDUCTIONconductingcircularplacedcentrescoinciding

More ELECTROMAGNETIC INDUCTION Questions

View all

A conducting circular loop of face area $2.5 \times 10^{-3} \text{ m}^2$ is placed perpendicular to a magnetic field which varies as $B=0.5 \sin(100\pi t) \text{ T}$. The magnitude of induced EMF at time $t=0 \text{ s}$ is:

A.$0.125\pi \text{ mV}$
B.$125\pi \text{ mV}$
C.$125\pi \text{ V}$
D.$12.5\pi \text{ mV}$
MediumSolve

A coil of resistance $400\Omega$ is placed in a magnetic field. If the magnetic flux $\phi\;(\text{Wb})$ linked with the coil varies with time $t\;(\text{sec})$ as $\phi=50t^2+4$. The current in the coil at $t=2\text{s}$ is:

A.0.5A
B.0.1A
C.2A
D.1A
EasySolve

A wooden stick of length $3l$ is rotated about an end with constant angular velocity $\omega$ in a uniform magnetic field $B$ perpendicular to the plane of motion. If the upper one third of its length is coated with copper, the potential difference across the whole length of the stick is:

A.$\frac{9B\omega l^2}{2}$
B.$\frac{4B\omega l^2}{2}$
C.$\frac{5B\omega l^2}{2}$
D.$\frac{B\omega l^2}{2}$
MediumSolve

The primary and secondary coils of a transformer have 50 and 1500 turns respectively. If the magnetic flux $\phi$ linked with the primary coil is given by $\phi = \phi_0 + 4t$, where $\phi$ is in Weber, $t$ is time in seconds, and $\phi_0$ is a constant, the output voltage across the secondary coil is:

A.90 V
B.120 V
C.220 V
D.30 V
EasySolve

In which of the following devices, the eddy current effect is not used?

A.Electric heater
B.Induction furnace
C.Magnetic braking in train
D.Electromagnet
EasySolve

The current in an inductor of self-inductance $4 \text{ H}$ changes from $4 \text{ A}$ to $2 \text{ A}$ in $1 \text{ s}$. The emf induced in the coil is:

A.-2 V
B.2 V
C.-4 V
D.8 V
EasySolve

In the above diagram, a strong bar magnet is moving towards solenoid-2 from solenoid-1. The direction of induced current in solenoid-1 and that in solenoid-2, respectively, are through the directions:

A.$B \to A$ and $C \to D$
B.$A \to B$ and $C \to D$
C.$B \to A$ and $D \to C$
D.$A \to B$ and $D \to C$
MediumSolve

A rod of length $L$ rotates with a small uniform angular velocity $\omega$ about its perpendicular bisector. A uniform magnetic field $B$ exists parallel to the axis of rotation. The potential difference between the centre of the rod and an end is:

A.$\frac{B\omega L^2}{8}$
B.$\frac{B\omega L^2}{2}$
C.$\frac{B\omega L^2}{4}$
D.zero
EasySolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →