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The best suited curve showing the variations of susceptibility ($\chi$) of a paramagnetic material in free space with temperature ($T$) is:
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in the equilibrium state. The energy required to rotate it by $60^\circ$ is $W$. Now the torque required to keep the magnet in this new position is:
Curie temperature is the temperature above which:
Two similar springs $P$ and $Q$ have spring constants $k_P$ and $k_Q$, such that $k_P > k_Q$. They are stretched, first by the same amount (case a), then by the same force (case b). The work done by the springs $W_P$ and $W_Q$ are related as, in case (a) and case (b), respectively:
A uniform force of $(3\hat{i} + \hat{j})$ N acts on a particle of mass 2 kg. The particle is displaced from the position $(2\hat{i} + \hat{k})$ m to the position $(4\hat{i} + 3\hat{j} - \hat{k})$ m. The work done by the force on the particle is:
The relation amongst the three elements of Earth's magnetic field, namely horizontal component $H$, vertical component $V$ and dip angle $\delta$ is: ($B_E$ = total magnetic field):
Match List-I with List-II: | List-I (IUPAC official name) | List-II (IUPAC Symbol) | | :--- | :--- | | A. Mendelevium | I. Mt | | B. Meitnerium | II. Mc | | C. Moscovium | III. No | | D. Nobelium | IV. Md |
Given below are two statements: Assertion (A): Gauss's law for magnetism states that the net magnetic flux through any closed surface is zero. Reason (R): The magnetic monopoles do not exist. North and South poles occur in pairs, allowing vanishing net magnetic flux through the surface.
Sucrose on hydrolysis gives:
Ionized hydrogen atoms and $\alpha$-particles with same momenta enters perpendicular to a constant magnetic field, B. The ratio of their radii of their paths $r_H : r_\alpha$ will be :
A body of mass $M$ at rest explodes into three pieces, two of which of mass $M/4$ each are thrown off in perpendicular directions with velocities of $3 \text{ m/s}$ and $4 \text{ m/s}$ respectively. The third piece will be thrown off with a velocity of:
A cord is used to lower vertically a block of mass $M$ by a distance $d$ with constant downward acceleration $\frac{g}{4}$. Work done by the cord on the block is:
Match List-I with List-II. **List-I (Material)** (A) Diamagnet (B) Paramagnet (C) Soft ferromagnet (D) Hard ferromagnet **List-II (Example)** (I) Alnico (II) Copper (III) Aluminium (IV) Gadolinium Choose the correct answer from the options given below:
A block of mass $50 \text{ kg}$ slides over a horizontal distance of $1 \text{ m}$. If the coefficient of friction between their surfaces is $0.2$, then work done against friction is:
Force F on a particle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12 m is
A uniform force of $(3\hat{i} + \hat{j}) \text{ N}$ acts on a particle of mass $2 \text{ kg}$. Hence the particle is displaced from position $(2\hat{i} + \hat{k}) \text{ m}$ to position $(4\hat{i} + 3\hat{j} - \hat{k}) \text{ m}$. The work done by the force on the particle is:
The cylindrical tube of a spray pump has radius $R$, one end of which has $n$ fine holes, each of radius $r$. If the speed of the liquid in the tube is $v$, the speed of the ejection of the liquid through the holes is:
Three liquids of densities $\rho_1, \rho_2$ and $\rho_3$ (with $\rho_1 > \rho_2 > \rho_3$), having the same value of surface tension $T$, rise to the same height in three identical capillaries. The angles of contact $\theta_1, \theta_2$ and $\theta_3$ obey:
An explosion blows a rock into three parts. Two parts go off at right angles to each other. These two are, $1\text{ kg}$ first part moving with a velocity of $12\text{ m s}^{-1}$ and $2\text{ kg}$ second part moving with a velocity of $8\text{ m s}^{-1}$. If the third part flies off with a velocity of $4\text{ m s}^{-1}$, its mass would be:
The cylindrical tube of a spray pump has radius $R$, one end of which has $n$ fine holes, each of radius $r$. If the speed of the liquid in the tube is $v$, then the speed of ejection of the liquid through the holes will be: