NEET Chemical Bonding and Molecular Structure — Set 12

Question 1

The bond angle in $ \ce{BF3} $ is:

Accepted Answer

In $ \ce{BF3} $, boron is $ sp^2 $ hybridized with three bonding pairs and no lone pairs, resulting in a trigonal planar shape with a 120° bond angle.

Question 2

Which molecule has a bond order of 1 and is paramagnetic?

Accepted Answer

For $ \ce{B2} $: $ (\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^1 (\pi 2p_y)^1 $. Bonding = 6, antibonding = 4. Bond order = $ \frac{6 - 4}{2} = 1 $, with 2 unpaired electrons (paramagnetic).

Question 3

Which molecule contains a double bond and has a bond length of approximately 123 pm?

Accepted Answer

In $ \ce{CO2} $, each $ \ce{C=O} $ double bond has a bond length of ~123 pm, shorter than $ \ce{C=C} $ in ethene (134 pm) due to higher bond strength.

NEET Chemistry: Chemical Bonding and Molecular Structure — Practice Set 12

Q1. The bond angle in \( \ce{BF3} \) is:

Q2. Which molecule has a bond order of 1 and is paramagnetic?

Q3. Which molecule contains a double bond and has a bond length of approximately 123 pm?

Q4. The shape of \( \ce{I3^-} \) ion is:

Q5. Which ion achieves a stable octet configuration by losing electrons, resulting in a +3 charge?

Q6. The hybridization of carbon in \( \ce{CH2=CH2} \) (ethene) is:

Q7. The hybridization of the central atom in \( \ce{SO2} \) is:

Q8. The total number of sigma and pi bonds in \( \ce{C3H4} \) (propyne) is:

Q9. Which species is diamagnetic and has a bond order of 2.5?

Q10. The hybridization of arsenic in \( \ce{AsF5} \) is: