NEET Chemical Bonding and Molecular Structure — Set 6

Question 1

The hybridization of bromine in $ \ce{BrF5} $ is:

Accepted Answer

In $ \ce{BrF5} $, bromine has 6 electron pairs (5 bonding, 1 lone), requiring $ sp^3d^2 $ hybridization, forming a square pyramidal shape.

Question 2

The bond angle in $ \ce{NH3} $ is approximately:

Accepted Answer

In $ \ce{NH3} $, nitrogen is $ sp^3 $ hybridized with one lone pair, reducing the bond angle from 109.5° to 107° due to lone pair-bond pair repulsion.

Question 3

The hybridization of oxygen in $ \ce{H2O} $ is:

Accepted Answer

In $ \ce{H2O} $, oxygen has four electron pairs (two bonding, two lone), requiring $ sp^3 $ hybridization.

NEET Chemistry: Chemical Bonding and Molecular Structure — Practice Set 6

Q1. The hybridization of bromine in \( \ce{BrF5} \) is:

Q2. The bond angle in \( \ce{NH3} \) is approximately:

Q3. The hybridization of oxygen in \( \ce{H2O} \) is:

Q4. Which molecule has the longest bond length among those with a single bond?

Q5. The hybridization of phosphorus in \( \ce{PH3} \) is:

Q6. Which molecule has a linear shape with a bond angle of 180°?

Q7. The bond order of \( \ce{B2} \) molecule is:

Q8. The hybridization of sulfur in \( \ce{SF2} \) is:

Q9. The hybridization of sulfur in \( \ce{SF4} \) is:

Q10. The shape of \( \ce{IF5} \) molecule is: