NEET Chemical Bonding and Molecular Structure — Set 4

Question 1

Which ion achieves a stable noble gas configuration by gaining two electrons?

Accepted Answer

Oxygen (O) has $ 1s^2 2s^2 2p^4 $. Gaining 2 electrons forms $ \ce{O^2-} $ with $ 1s^2 2s^2 2p^6 $, matching $ \ce{Ne} $.

Question 2

The number of lone pairs on chlorine in $ \ce{ClF5} $ is:

Accepted Answer

In $ \ce{ClF5} $, chlorine has 7 valence electrons, forms 5 bonds (10 electrons used), leaving 2 electrons as 1 lone pair in a $ sp^3d^2 $ hybridized state.

Question 3

The hybridization of boron in $ \ce{B2H6} $ (diborane) is:

Accepted Answer

In $ \ce{B2H6} $, each boron is $ sp^3 $ hybridized, forming two normal $ \ce{B-H} $ bonds and two 3-center-2-electron bridge bonds.

NEET Chemistry: Chemical Bonding and Molecular Structure — Practice Set 4

Q1. Which ion achieves a stable noble gas configuration by gaining two electrons?

Q2. The number of lone pairs on chlorine in \( \ce{ClF5} \) is:

Q3. The hybridization of boron in \( \ce{B2H6} \) (diborane) is:

Q4. Which molecule has a bond angle of approximately 102° due to lone pair repulsion?

Q5. The number of sigma bonds in \( \ce{C2H4} \) is:

Q6. Which species is paramagnetic and has a bond order of 1.5?

Q7. Which molecule is paramagnetic due to unpaired electrons?

Q8. Which molecule has a coordinate bond formed by donation of a lone pair?

Q9. Which molecule has an intramolecular hydrogen bond?

Q10. The hybridization of carbon in \( \ce{HCN} \) is: