NEET Chemical Bonding and Molecular Structure — Set 3

Question 1

The number of lone pairs on sulfur in $ \ce{SF4} $ is:

Accepted Answer

In $ \ce{SF4} $, sulfur has 6 valence electrons, forms 4 bonds (8 electrons used), leaving 2 electrons as 1 lone pair in a $ sp^3d $ hybridized state.

Question 2

Which species is diamagnetic and has a bond order of 3?

Accepted Answer

For $ \ce{N2} $: $ (\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\sigma 2p_z)^2 $. Bonding = 10, antibonding = 4. Bond order = $ \frac{10 - 4}{2} = 3 $, with all electrons paired (diamagnetic).

Question 3

Which molecule has a bond angle of approximately 107° due to lone pair repulsion?

Accepted Answer

In $ \ce{NH3} $, nitrogen is $ sp^3 $ hybridized with 4 electron pairs (3 bonding, 1 lone), reducing the bond angle to ~107° due to lone pair repulsion.

NEET Chemistry: Chemical Bonding and Molecular Structure — Practice Set 3

Q1. The number of lone pairs on sulfur in \( \ce{SF4} \) is:

Q2. Which species is diamagnetic and has a bond order of 3?

Q3. Which molecule has a bond angle of approximately 107° due to lone pair repulsion?

Q4. The shape of \( \ce{ClF5} \) molecule is:

Q5. Which molecule violates the octet rule by having fewer than 8 electrons around the central atom?

Q6. Which species has a bond order of 1.5 due to the addition of an electron to a diatomic molecule?

Q7. Which molecule has a bond angle of approximately 90° in a square pyramidal shape?

Q8. The hybridization of phosphorus in \( \ce{PCl5} \) is:

Q9. The number of sigma bonds in \( \ce{C4H10} \) (butane) is:

Q10. The hybridization of sulfur in \( \ce{SO3} \) is: