NEET Chemical Bonding and Molecular Structure — Set 7

Question 1

The number of lone pairs on the central atom in $ \ce{XeF2} $ is:

Accepted Answer

In $ \ce{XeF2} $, xenon has 8 valence electrons and forms 2 bonds (4 electrons used), leaving 4 electrons as 3 lone pairs. With $ sp^3d $ hybridization, the 5 electron pairs (2 bonding, 3 lone) result in a trigonal bipyramidal electron geometry and a linear molecular shape.

Question 2

The hybridization of carbon in $ \ce{CS2} $ is:

Accepted Answer

In $ \ce{CS2} $, carbon has 2 double bonds (2 bonding domains), requiring $ sp $ hybridization for a linear shape.

Question 3

The number of lone pairs on iodine in $ \ce{IF5} $ is:

Accepted Answer

In $ \ce{IF5} $, iodine has 7 valence electrons, forms 5 bonds (10 electrons used), leaving 2 electrons as 1 lone pair in a $ sp^3d^2 $ hybridized state.

NEET Chemistry: Chemical Bonding and Molecular Structure — Practice Set 7

Q1. The number of lone pairs on the central atom in \( \ce{XeF2} \) is:

Q2. The hybridization of carbon in \( \ce{CS2} \) is:

Q3. The number of lone pairs on iodine in \( \ce{IF5} \) is:

Q4. In which molecule does hydrogen bonding significantly influence its properties?

Q5. The bond order of \( \ce{B2^-} \) ion, based on molecular orbital theory, is:

Q6. Which species has a bond order of 2.5 and is paramagnetic?

Q7. Which molecule has a triple bond and exhibits linear geometry?

Q8. The number of pi bonds in \( \ce{C2H2} \) is:

Q9. The stability of an ionic compound is primarily due to:

Q10. The hybridization of carbon in \( \ce{C2H6} \) is: