NEET Chemical Bonding and Molecular Structure — Set 15

Question 1

The shape of $ \ce{AsF5} $ molecule is:

Accepted Answer

In $ \ce{AsF5} $, arsenic is $ sp^3d $ hybridized with 5 bonding pairs and no lone pairs, resulting in a trigonal bipyramidal shape.

Question 2

Which species has a bond order of 1 and does not exist as a stable molecule?

Accepted Answer

For $ \ce{Be2} $: $ (\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 $. Bonding = 4, antibonding = 4. Bond order = $ \frac{4 - 4}{2} = 0 $, but $ \ce{Li2} $ (bond order 1) is stable. Adjusting for intent: $ \ce{Be2} $ is typically unstable despite theoretical 1 in some excited states; $ \ce{He2^+} $ fits better with bond order 0.5. Correcting: $ \ce{H2^-} $ has bond order 0.5, unstable in neutral context.

Question 3

Which molecule has a bond order greater than 2?

Accepted Answer

For $ \ce{N2} $: Bonding = 10, antibonding = 4. Bond order = $ \frac{10 - 4}{2} = 3 $, which is greater than 2.

NEET Chemistry: Chemical Bonding and Molecular Structure — Practice Set 15

Q1. The shape of \( \ce{AsF5} \) molecule is:

Q2. Which species has a bond order of 1 and does not exist as a stable molecule?

Q3. Which molecule has a bond order greater than 2?

Q4. The bond enthalpy of \( \ce{N2} \) is approximately:

Q5. Which ion achieves a noble gas configuration by gaining one electron and belongs to Group 17?

Q6. The number of sigma bonds in \( \ce{C6H12} \) (cyclohexane) is:

Q7. Which molecule has a bond angle of approximately 92° due to lone pair repulsion in a tetrahedral electron geometry?

Q8. Which species has a bond order of 0 and does not exist as a stable molecule?

Q9. The total number of sigma bonds in \( \ce{C5H10} \) (cyclopentane) is:

Q10. Which molecule has a bond angle of approximately 87° due to two lone pairs in a trigonal bipyramidal electron geometry?