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NEET CHEMISTRYChemical KineticsMedium

Question

A reaction having equal energies of activation for forward and reverse reactions has

A

ΔS=0\Delta S = 0

B

ΔG=0\Delta G = 0

C

ΔH=0\Delta H = 0

D

ΔH=ΔG=ΔS=0\Delta H = \Delta G = \Delta S = 0

Step-by-Step Solution

The enthalpy change of a reaction (ΔH\Delta H) is equal to the difference between the activation energy of the forward reaction (Ea(forward)E_{a(\text{forward})}) and the activation energy of the reverse/backward reaction (Ea(reverse)E_{a(\text{reverse})}). This relationship can be expressed as: ΔH=Ea(forward)Ea(reverse)\Delta H = E_{a(\text{forward})} - E_{a(\text{reverse})} Given that the activation energies for both the forward and reverse reactions are equal (Ea(forward)=Ea(reverse)E_{a(\text{forward})} = E_{a(\text{reverse})}), their difference becomes zero. Therefore, ΔH=0\Delta H = 0.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Kinetics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Kineticsreactionhavingenergiesactivationforward

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