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NEET CHEMISTRYHydrocarbonsMedium

Question

An alkene reacts in accordance with Markownikoff's rule to give a product of 1-chloro-1-methylcyclohexane with HCl. The possible alkene is:

A

(Option 1 Structure Missing)

B

(Option 2 Structure Missing)

C

Both 1 and 2

D

(Option 4 Structure Missing)

Step-by-Step Solution

  1. Reaction: The reaction involves the addition of HClHCl to an alkene. This is an electrophilic addition reaction governed by Markovnikov's Rule .
  2. Product Analysis: The product is 1-chloro-1-methylcyclohexane. This structure has a chlorine atom and a methyl group both attached to the same carbon (C1) of the cyclohexane ring. This is a tertiary alkyl halide.
  3. Retrosynthetic Analysis (Identifying Reactants): To form this product via Markovnikov addition:
  • The proton (H+H^+) from HCl must add to a carbon of the double bond to form the stable tertiary carbocation at C1 (where the methyl group is attached).
  • The chloride ion (Cl−Cl^-) then attacks this tertiary carbocation.
  1. Possible Alkenes: Two alkenes can generate this specific tertiary carbocation:
  • 1-Methylcyclohexene: The double bond is between C1 (with methyl) and C2. H+H^+ adds to C2 (less substituted), generating the 3∘3^{\circ} carbocation at C1.
  • Methylenecyclohexane: The double bond is exocyclic (between the ring carbon and an external CH2CH_2). H+H^+ adds to the external CH2CH_2, generating the 3∘3^{\circ} carbocation at the ring carbon.
  1. Conclusion: Both 1-Methylcyclohexene and Methylenecyclohexane yield the same major product, 1-chloro-1-methylcyclohexane, upon reaction with HCl. Therefore, the answer is likely "Both 1 and 2" assuming these are the structures for options 1 and 2.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Hydrocarbons. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYHydrocarbonsalkenereactsaccordancemarkownikoffsproduct

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Phenylacetylene undergoes a reaction with dilute $\text{H}_2\text{SO}_4$ in the presence of $\text{HgSO}_4$ to yield:

A.Option 1 (Structure missing)
B.Option 2 (Structure missing)
C.Option 3 (Structure missing)
D.Option 4 (Structure missing)
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A.(Option 1 Structure Missing)
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C.4
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A.The eclipsed conformation of ethane is more stable than staggered conformation because eclipsed conformation has no torsional strain.
B.The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has a torsional strain.
C.The staggered conformation of ethane is more stable than eclipsed conformation because staggered conformation has no torsional strain.
D.The staggered conformation of ethane is less stable than eclipsed conformation because staggered conformation has a torsional strain.
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