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NEET CHEMISTRYEquilibriumMedium

Question

For the reversible reaction, N2(g)+3H2(g)2NH3(g)+HeatN_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + \text{Heat}, the equilibrium shifts in the forward direction:

A

By increasing the concentration of NH3(g)NH_3(g)

B

By decreasing the pressure

C

By decreasing the concentrations of N2(g)N_2(g) and H2(g)H_2(g)

D

By increasing pressure and decreasing temperature

Step-by-Step Solution

According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in temperature, pressure, or concentration, the equilibrium shifts in a direction that counteracts the change.

  1. Temperature: The given reaction is exothermic (heat is released as a product). Lowering the temperature removes heat, which favours the forward (exothermic) reaction.
  2. Pressure: The forward reaction proceeds with a decrease in the number of gaseous moles (1 mol N2+3 mol H2=4 moles1 \text{ mol } N_2 + 3 \text{ mol } H_2 = 4 \text{ moles} on the reactant side; 2 moles NH32 \text{ moles } NH_3 on the product side). Increasing the pressure shifts the equilibrium towards the side with fewer gaseous moles to reduce the pressure, which is the forward direction. Therefore, low temperature and high pressure favour the forward reaction.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Equilibrium. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYEquilibriumreversiblereactionrightleftharpoonstextheatequilibrium

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A.3.9
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Amongst the given options, which of the following molecules/ions acts as a Lewis acid?

A.$\text{OH}^-$
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Boric acid is an acid because its molecule

A.contains replaceable H⁺ ion
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A.$2 \times 10^{-4} \text{ mol/L}$
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In qualitative analysis, the metals of Group I can be separated from other ions by precipitating them as chloride salts. A solution initially contains $\text{Ag}^+$ and $\text{Pb}^{2+}$ at a concentration of $0.10 \text{ M}$. Aqueous $\text{HCl}$ is added to this solution until the $\text{Cl}^-$ concentration is $0.10 \text{ M}$. What will the concentration of $\text{Ag}^+$ and $\text{Pb}^{2+}$ at equilibrium? ($K_{sp}$ for $\text{AgCl} = 1.8 \times 10^{-10}$, $K_{sp}$ for $\text{PbCl}_2 = 1.7 \times 10^{-5}$)

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