Percentage of C, H & N in a compound is given as follows: C=40%; H=13.33%; N=46.67% The empirical formula of t

Question

Percentage of C, H & N in a compound is given as follows: C=40%; H=13.33%; N=46.67% The empirical formula of the compound will be:

Accepted Answer

1. **Determine the number of moles of each element:** Assume a $100	ext{ g}$ sample of the compound.
   - Moles of Carbon (C): $\frac{40	ext{ g}}{12	ext{ g/mol}} = 3.33	ext{ mol}$
   - Moles of Hydrogen (H): $\frac{13.33	ext{ g}}{1	ext{ g/mol}} = 13.33	ext{ mol}$
   - Moles of Nitrogen (N): $\frac{46.67	ext{ g}}{14	ext{ g/mol}} = 3.33	ext{ mol}$
2. **Determine the simplest molar ratio:** Divide the moles of each element by the smallest molar value ($3.33	ext{ mol}$).
   - C: $\frac{3.33}{3.33} = 1$
   - H: $\frac{13.33}{3.33} \approx 4$
   - N: $\frac{3.33}{3.33} = 1$
3. **Conclusion:** The simplest whole number ratio of C:H:N is $1:4:1$. Therefore, the empirical formula is $	ext{CH}_4	ext{N}$.

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