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NEET CHEMISTRYChemical Bonding and Molecular StructureMedium

Question

The correct order of C-O bond length among CO, CO32−CO_3^{2-}, and CO2CO_2 is:

A

CO2<CO32−<COCO_2 < CO_3^{2-} < CO

B

CO<CO32−<CO2CO < CO_3^{2-} < CO_2

C

CO32−<CO2<COCO_3^{2-} < CO_2 < CO

D

CO<CO2<CO32−CO < CO_2 < CO_3^{2-}

Step-by-Step Solution

  1. Relationship: Bond length is inversely proportional to bond order. Higher bond order implies stronger attraction and shorter bond length.
  2. Analyze CO: Carbon monoxide has a triple bond between Carbon and Oxygen. Bond Order = 3.
  3. Analyze CO2CO_2: Carbon dioxide (O=C=OO=C=O) has double bonds between Carbon and Oxygen. Bond Order = 2.
  4. Analyze CO32−CO_3^{2-}: The carbonate ion exhibits resonance. The double bond is delocalized over three C-O bonds. Bond Order = Total BondsResonance Structures=43≈1.33\frac{\text{Total Bonds}}{\text{Resonance Structures}} = \frac{4}{3} \approx 1.33.
  5. Comparison:
  • Bond Order: CO(3)>CO2(2)>CO32−(1.33)CO (3) > CO_2 (2) > CO_3^{2-} (1.33)
  • Bond Length: CO<CO2<CO32−CO < CO_2 < CO_3^{2-}

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structurecorrectlength

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