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NEET CHEMISTRYChemical Bonding and Molecular StructureEasy

Question

Which of the following is a paramagnetic compound?

A

N₂

B

H₂

C

Li₂

D

O₂

Step-by-Step Solution

  1. Definition: A substance is paramagnetic if it contains unpaired electrons. It is diamagnetic if all electrons are paired.
  2. Analyze N2N_2 (14 electrons): Configuration is σ1s2σ1s∗2σ2s2σ2s∗2(π2px2=π2py2)σ2pz2\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} (\pi_{2p_x}^2 = \pi_{2p_y}^2) \sigma_{2p_z}^2. All electrons are paired. Diamagnetic.
  3. Analyze H2H_2 (2 electrons): Configuration is σ1s2\sigma_{1s}^2. All electrons paired. Diamagnetic.
  4. Analyze Li2Li_2 (6 electrons): Configuration is σ1s2σ1s∗2σ2s2\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2. All electrons paired. Diamagnetic.
  5. Analyze O2O_2 (16 electrons): Configuration is σ1s2σ1s∗2σ2s2σ2s∗2σ2pz2(π2px2=π2py2)(π2px∗1=π2py∗1)\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \sigma_{2p_z}^2 (\pi_{2p_x}^2 = \pi_{2p_y}^2) (\pi_{2p_x}^{*1} = \pi_{2p_y}^{*1}). The last two electrons occupy the degenerate antibonding π∗\pi^* orbitals singly (Hund's Rule). Therefore, it has 2 unpaired electrons and is Paramagnetic.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structurefollowingparamagneticcompound

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