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NEET CHEMISTRYSome Basic Concepts of ChemistryEasy

Question

The mass of CO2CO_2 produced by heating 20 g of 20% pure limestone, as per the equation given below, is: CaCO3(s)heatCaO(s)+CO2(g)CaCO_3(s) \xrightarrow{\text{heat}} CaO(s) + CO_2(g)

A

1.32 g

B

1.12 g

C

1.76 g

D

2.64 g

Step-by-Step Solution

  1. Calculate Mass of Pure Reactant:
  • Total mass of limestone sample = 20 g20 \text{ g}.
  • Percentage purity = 20%20\%.
  • Mass of pure CaCO3=20 g×20100=4 gCaCO_3 = 20 \text{ g} \times \frac{20}{100} = 4 \text{ g}.
  1. Determine Molar Masses:
  • Molar Mass of CaCO3(1×40+1×12+3×16)=100 g mol1CaCO_3 (1 \times 40 + 1 \times 12 + 3 \times 16) = 100 \text{ g mol}^{-1} [Class 12 Chemistry, Ch 1, Example 1.2].
  • Molar Mass of CO2(1×12+2×16)=44 g mol1CO_2 (1 \times 12 + 2 \times 16) = 44 \text{ g mol}^{-1}.
  1. Apply Stoichiometry:
  • According to the balanced equation, 1 mol CaCO31 \text{ mol } CaCO_3 yields 1 mol CO21 \text{ mol } CO_2.
  • 100 g CaCO3100 \text{ g } CaCO_3 yields 44 g CO244 \text{ g } CO_2.
  • Therefore, 4 g CaCO34 \text{ g } CaCO_3 yields: Mass of CO2=44100×4=1.76 g\text{Mass of } CO_2 = \frac{44}{100} \times 4 = 1.76 \text{ g}

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Some Basic Concepts of Chemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYSome Basic Concepts of Chemistryproducedheatinglimestoneequationxrightarrowtextheat

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