back to directory
NEET CHEMISTRYAminesMedium

Question

The nitration of aniline in a strong acidic medium results in the formation of m-nitroaniline because:

A

In spite of substituents, the nitro group always goes to only the m-position.

B

In electrophilic substitution reactions, the amino group is meta-directive.

C

In the absence of substituents, the nitro group always goes to only m-position.

D

In an acidic (strong) medium, aniline is present as an anilinium ion.

Step-by-Step Solution

In a strongly acidic medium, the basic amino group (NH2-NH_2) of aniline readily accepts a proton to form an anilinium ion (NH3+-NH_3^+). While the free amino group is electron-donating and ortho/para-directing, the anilinium ion carries a positive charge on nitrogen, making it strongly electron-withdrawing via the I-I effect. This deactivates the benzene ring and directs the incoming electrophile (nitro group) to the meta-position. Consequently, nitration of aniline in a strongly acidic medium yields a significant proportion of m-nitroaniline.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Amines. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYAminesnitrationanilinestrongacidicmedium

More Amines Questions

View all

The products formed when Aniline reacts with $Br_2$ water, and $NaNO_2/HCl$ will be, respectively:

A.p-Bromoaniline; p-Chloroaniline
B.2,4,6-Tribromoaniline; p-Chloroaniline
C.2,4,6-Tribromoaniline; Benzenediazonium chloride
D.p-Bromoaniline; Benzenediazonium chloride
MediumSolve

Aniline gives a set of the following reactions that yielded a coloured product 'Y'. The structure of 'Y' is: (Note: Reaction scheme is missing from the provided text)

A.Option 1
B.Option 2
C.Option 3
D.Option 4
MediumSolve

The structure of C in the below-mentioned reaction is: (Note: Reaction scheme is missing from the provided text)

A.Option 1
B.Option 2
C.Option 3
D.Option 4
MediumSolve

What results from the electrolytic reduction of nitrobenzene in a highly acidic medium?

A.p-Aminophenol
B.Azoxybenzene
C.Azobenzene
D.Aniline
MediumSolve

The reagent required to convert acetamide into methyl amine is:

A.$NaOH/Br_2$
B.Sodalime
C.Hot conc. $H_2SO_4$
D.$PCl_5$
EasySolve

D is N-methyl aniline in the given below sequence of reaction: $A \xrightarrow{\text{reduction}} B \xrightarrow{CHCl_3/KOH} C \xrightarrow{\text{reduction}} D$. Structure of A can be:

A.Option 1 (Missing)
B.Nitrobenzene
C.CH3NH2
D.Option 4 (Missing)
MediumSolve

Which of the following statements about primary amines is false?

A.Alkyl amines are stronger bases than aryl amines
B.Alkyl amines react with nitrous acid to produce alcohols
C.Aryl amines react with nitrous acid to produce phenols
D.Alkyl amines are stronger bases than ammonia
MediumSolve

What is the correct order of the methyl-substituted amines' basic strength in an aqueous solution?

A.$CH_3NH_2 > (CH_3)_2NH > (CH_3)_3N$
B.$(CH_3)_2NH > CH_3NH_2 > (CH_3)_3N$
C.$(CH_3)_3N > CH_3NH_2 > (CH_3)_2NH$
D.$(CH_3)_2NH > (CH_3)_3N > CH_3NH_2$
MediumSolve

This neet chemistry practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice chemistry sets →