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NEET CHEMISTRYHydrocarbonsMedium

Question

The products that formed when the following compound is treated with Br2\text{Br}_2 in the presence of FeBr3\text{FeBr}_3 are:

A

Option 1 (Structure missing)

B

Option 2 (Structure missing)

C

Option 3 (Structure missing)

D

Option 4 (Structure missing)

Step-by-Step Solution

The reaction of an aromatic compound with halogens like Br2\text{Br}_2 in the presence of a Lewis acid (such as anhydrous FeBr3\text{FeBr}_3 or AlCl3\text{AlCl}_3) is an electrophilic aromatic substitution reaction . The Lewis acid helps generate the active electrophile (Br+\text{Br}^+), which attacks the electron-rich benzene ring . The exact position of the newly attached bromine atom(s)—whether ortho, meta, or para—depends entirely on the directive influence of the functional groups already present on the parent aromatic compound . Because the structure of the starting compound is missing from the input data, the specific product cannot be deduced.

Note: Option 4 is marked correct based solely on the provided probable answer.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Hydrocarbons. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYHydrocarbonsproductsformedfollowingcompoundtreated

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Phenylacetylene undergoes a reaction with dilute $\text{H}_2\text{SO}_4$ in the presence of $\text{HgSO}_4$ to yield:

A.Option 1 (Structure missing)
B.Option 2 (Structure missing)
C.Option 3 (Structure missing)
D.Option 4 (Structure missing)
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The reaction among the following that proceeds through an electrophilic substitution reaction is:

A.(Option 1 Structure Missing)
B.(Option 2 Structure Missing)
C.4
D.(Option 4 Structure Missing)
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The order of decreasing reactivity towards an electrophilic reagent for the following compounds is: (i) Benzene (ii) Toluene (iii) Chlorobenzene (iv) Phenol

A.(i) > (ii) > (iii) > (iv)
B.(ii) > (iv) > (i) > (iii)
C.(iv) > (iii) > (ii) > (i)
D.(iv) > (ii) > (i) > (iii)
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X and Y in the above-mentioned reaction are respectively:

A.X = 2–Butyne; Y = 3–Hexyne
B.X = 2-Butyne; Y = 2-Hexyne
C.X = 1-Butyne; Y = 2-Hexyne
D.X = 1-Butyne; Y = 3–Hexyne
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Match the bond line structures of hydrocarbons given in List-I with the corresponding boiling points given in List-II. List-II (Boiling point in K): (i) 300.9 (ii) 282.5 (iii) 309.1 (iv) 341.9 Choose the correct answer from the options given below:

A.(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
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D.(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
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The dihedral angle of the least stable conformer of ethane is:

A.$60^{\circ}$
B.$0^{\circ}$
C.$120^{\circ}$
D.$180^{\circ}$
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A.0
B.1
C.2
D.3
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The correct statement regarding the comparison of staggered and eclipsed conformations of ethane is:

A.The eclipsed conformation of ethane is more stable than staggered conformation because eclipsed conformation has no torsional strain.
B.The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has a torsional strain.
C.The staggered conformation of ethane is more stable than eclipsed conformation because staggered conformation has no torsional strain.
D.The staggered conformation of ethane is less stable than eclipsed conformation because staggered conformation has a torsional strain.
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